Question

Determine the number of moles present in 22.4 g of silver nitrate.

a. 0.1 moles
b. 0.2 moles
c. 0.3 moles
d. 0.4 moles

Answer 1

To find moles in 22.4 g of silver nitrate, divide its mass by its molar mass (169.87 g/mol), resulting in approximately 0.1318 moles, which is closest to 0.1 moles.

Step-by-step explanation:

To determine the number of moles present in 22.4 g of silver nitrate, we first need to calculate the molar mass of silver nitrate (AgNO3).

The molar mass of this compound is the sum of the atomic masses of silver (Ag, 107.87 g/mol), nitrogen (N, 14.01 g/mol), and oxygen (O, 16.00 g/mol × 3), which equals 169.87 g/mol.

Next, we use this molar mass to convert the mass of silver nitrate to moles:

1. Divide the mass of the compound in grams by its molar mass.
2. 22.4 g ÷ 169.87 g/mol = 0.1318 moles.

Therefore, the closest answer to the number of moles of silver nitrate in 22.4 g is 0.1 moles (option a).