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Claude has 7 paintings and he can paint 2 every week.

Clint has 10 paintings and he takes 2 weeks to paint
1 picture. How many weeks (w) will it be before Claude
has as many paintings as Clint?
p = 2w +7
p = {w + 10
[?] weeks

User Guidsen
by
8.1k points

1 Answer

2 votes

Final answer:

It will take 10 weeks before Claude has as many paintings as Clint.

Step-by-step explanation:

To find out how many weeks it will take for Claude to have as many paintings as Clint, we need to set up an equation.

Claude paints 2 paintings every week, so the number of paintings he has after w weeks can be represented as 2w.

Clint takes 2 weeks to paint 1 painting, so the number of paintings he has after w weeks can be represented as {w + 10}.

We want to find the number of weeks when Claude has as many paintings as Clint, so we can set up the equation 2w = w + 10.

Now we can solve this equation:

2w = w + 10

w = 10

Therefore, it will take 10 weeks before Claude has as many paintings as Clint.

User Fingerprints
by
7.3k points
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