Question

A substance requires 27 J of heat to raise its temperature by 6°C. If the mass of the substance is 5 g, what is the specific heat of the substance?

Options:
A) 0.9 J/g°C
B) 1.2 J/g°C
C) 3.6 J/g°C
D) 4.5 J/g°C

Answer 1

The specific heat of the substance is calculated using the formula q = mcΔT. Given the values q = 27 J, m = 5 g, and ΔT = 6°C, the specific heat is found to be 0.9 J/g°C, which corresponds to option A.

Step-by-step explanation:

The specific heat of a substance is defined as the amount of heat energy required to raise the temperature of 1 gram of the substance by 1°C. To find the specific heat (c) of the substance in the question, we use the formula q = mcΔT, where q is the heat energy supplied, m is the mass of the substance, and ΔT is the change in temperature.

Given that q = 27 J, m = 5 g, and ΔT = 6°C, we can solve for c:

c = q / (mΔT) = 27 J / (5 g * 6°C) = 0.9 J/g°C.

Therefore, the correct option is A) 0.9 J/g°C and this is the specific heat of the substance.