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Find the magnitude of the sum of these two vectors : 15.00 mA 30.0 degrees 6.00 m?

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Final answer:

The magnitude and sign of a point charge are determined from the electric potential using the formula V = k*q/r. Given the potential of 5.00 x 10² V at a distance of 15.0 m, and knowing the potential is positive, the charge is positive and its magnitude can be calculated by rearranging the formula.

Step-by-step explanation:

To find the magnitude and sign of a point charge from its electric potential, one can use the formula for electric potential due to a point charge, which is V = k*q/r, where V is the electric potential, k is Coulomb's constant (8.99 x 109 Nm2/C2), q is the charge, and r is the distance from the charge. Inserting the given values, V = 5.00 x 102 V and r = 15.0 m, we can rearrange the equation to solve for q: q = V*r/k.

Therefore, the magnitude of the charge (q) is calculated as:

q = (5.00 x 102 V * 15.0 m) / (8.99 x 109 Nm2/C2)

Once the magnitude is calculated, the sign of the charge depends on whether the potential is positive (indicating a positive charge) or negative (indicating a negative charge). In this case, as the potential is positive, the charge would also be positive.

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