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If AC = 40, BD = 40, AB= 2x+3 and CD =3x-2 determine the value of x algebraically

User Jeff Ling
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1 Answer

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Final answer:

The value of x is found by setting the sum of AB and CD equal to AC and solving for x, which results in x being 7.8.

Step-by-step explanation:

To find the value of x algebraically when given AC = 40, BD = 40, AB = 2x + 3, and CD = 3x - 2, we start by observing that AC and BD are diagonals of a rectangle, line segment or otherwise intersecting lines that are equal in length.

We can set AB + CD equal to AC to find x:

2x + 3 + 3x - 2 = 40

5x + 1 = 40

5x = 39

x = 39/5

x = 7.8

Therefore, the value of x is 7.8.

User Stolho
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