Question

A wagon, initially traveling at a constant 1.5 m/s, starts going down a hill that creates

an acceleration of 1.0 m/s. What is the wagon's velocity 2.8 s after it starts accelerating
down the hill?

Answer 1

To calculate the wagon's velocity after accelerating for 2.8 seconds, use the formula v = u + at. With an initial velocity of 1.5 m/s and acceleration of 1.0 m/s², the final velocity is 4.3 m/s.

Step-by-step explanation:

The student's question is about calculating the velocity of a wagon after it has been accelerating down a hill for a given amount of time. To find the wagon's velocity after 2.8 seconds of accelerating down the hill, we can use the equation of motion v = u + at, where v is the final velocity, u is the initial velocity, a is acceleration, and t is time.

Given that the initial velocity u is 1.5 m/s, the acceleration a is 1.0 m/s², and the time t is 2.8 s, we can calculate:

v = u + at

v = 1.5 m/s + (1.0 m/s²)(2.8 s)

v = 1.5 m/s + 2.8 m/s

v = 4.3 m/s

Therefore, the wagon's velocity 2.8 seconds after starting to accelerate down the hill is 4.3 m/s.