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Write a linear equation given the x-intercept (2, 0) and y-intercept (0. -4)

a. y=-22 - 4
b. y=x+4
c. y= 4x + 2
d. y= 2.1 – 4

User Petriq
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1 Answer

2 votes

Final answer:

The equation of the line given the x-intercept (2, 0) and y-intercept (0, -4) is) y = 2x - 4.

The answer is option ⇒D

Step-by-step explanation:

To write a linear equation given the x-intercept (2, 0) and y-intercept (0, -4), we can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.

To find the slope, we can use the formula:

m = (y₂ - y₁) / (x₂ - x₁)

Using the given points, the slope is:

m = (-4 - 0) / (0 - 2) = -4 / -2 = 2

Now that we have the slope, we can substitute it into the slope-intercept form:

y = 2x + b

To find the value of b, we can substitute one of the given points into the equation. Let's use the y-intercept (0, -4):

-4 = 2(0) + b

-4 = b

Now we have the value of b

We have the slope, we can substitute it along with the y-intercept into the equation y = mx + b:

y = 2x - 4

So, the linear equation that passes through the x-intercept (2, 0) and the y-intercept (0, -4) is y = 2x - 4.

This equation represents a line with a slope of 2 and a y-intercept of -4. The slope of 2 means that for every increase of 1 in x, the corresponding y-value increases by 2. The y-intercept of -4 represents the point where the line intersects the y-axis.

The answer is option ⇒D

Your question is incomplete, but most probably the full question was:

Write a linear equation given the x-intercept (2, 0) and y-intercept (0. -4)

a. y= –2x - 4

b. y= x+4

c. y= 4x + 2

d. y= 2x – 4

User ReBa
by
8.4k points

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