Final answer:
The equation of the line given the x-intercept (2, 0) and y-intercept (0, -4) is) y = 2x - 4.
The answer is option ⇒D
Step-by-step explanation:
To write a linear equation given the x-intercept (2, 0) and y-intercept (0, -4), we can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.
To find the slope, we can use the formula:
m = (y₂ - y₁) / (x₂ - x₁)
Using the given points, the slope is:
m = (-4 - 0) / (0 - 2) = -4 / -2 = 2
Now that we have the slope, we can substitute it into the slope-intercept form:
y = 2x + b
To find the value of b, we can substitute one of the given points into the equation. Let's use the y-intercept (0, -4):
-4 = 2(0) + b
-4 = b
Now we have the value of b
We have the slope, we can substitute it along with the y-intercept into the equation y = mx + b:
y = 2x - 4
So, the linear equation that passes through the x-intercept (2, 0) and the y-intercept (0, -4) is y = 2x - 4.
This equation represents a line with a slope of 2 and a y-intercept of -4. The slope of 2 means that for every increase of 1 in x, the corresponding y-value increases by 2. The y-intercept of -4 represents the point where the line intersects the y-axis.
The answer is option ⇒D
Your question is incomplete, but most probably the full question was:
Write a linear equation given the x-intercept (2, 0) and y-intercept (0. -4)
a. y= –2x - 4
b. y= x+4
c. y= 4x + 2
d. y= 2x – 4