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A 18.2 kg blue marble moving at 26 m/s hits a 8.4 kg green marble at rest. If the blue marble comes to a complete stop afterward, what is the velocity of the green marble?

A. 6.11 m/s
B. 7.73 m/s
C. 8.56 m/s
D. 10.92 m/s

1 Answer

6 votes

Final answer:

To determine the velocity of the green marble after an 18.2 kg blue marble at 26 m/s hits it and comes to a stop, one applies the principle of conservation of momentum. The calculations indicate a velocity of 56.33 m/s for the green marble. So, none of the given options are correct.

Step-by-step explanation:

The question involves a collision between two marbles where momentum is conserved.

This scenario is a physics problem based on the conservation of linear momentum.

In a momentum conservation problem, the total momentum before the collision equals the total momentum after the collision.

In the given problem, an 18.2 kg blue marble moving at 26 m/s comes to a stop after hitting a stationary 8.4 kg green marble.

To find the velocity of the green marble, we use the conservation of momentum:

Total momentum before collision = Total momentum after collision

(18.2 kg × 26 m/s) + (8.4 kg × 0 m/s) = (18.2 kg × 0 m/s) + (8.4 kg × v)

473.2 kg·m/s = 8.4 kg × v

v = 473.2 kg·m/s / 8.4 kg

v = 56.33 m/s

None of the given options are correct.

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