Question

If you throw a ball at 35° and 10.0 m/s, what is the horizontal component of velocity?

A) 10 m/s
B) 8.2 m/s
C) 0.0 m/s
D) 5.7 m/s

Answer 1

The horizontal component of velocity for a ball thrown at 35° with an initial velocity of 10.0 m/s is approximately 8.2 m/s, calculated using the cosine function of the angle of projection.

Step-by-step explanation:

To determine the horizontal component of velocity when a ball is thrown at a certain angle, we use the cosine function. The given angle is 35°, and the initial velocity is 10.0 m/s. The horizontal velocity component (Vx) can be calculated using the formula Vx = V * cos(θ), where V is the initial velocity, and θ is the angle of projection.

Using this formula:

Vx = 10.0 m/s * cos(35°)

To find cos(35°), you can use a calculator:

cos(35°) ≈ 0.8192

Therefore, the horizontal component of velocity is:

Vx ≈ 10.0 m/s * 0.8192 ≈ 8.2 m/s

The correct answer to the question is B) 8.2 m/s.