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A calorimeter holds 75.0 g water at 26.0°C. A sample of hot copper is added to the water. The

final temperature of the water and copper is 39.0°C. What is the change in heat associated with
the change in the water's temperature? The specific heat capacity of water is 4.19 J/gºC.

A. 4100 J
B. 4.10 J
C. 4.10 J
D. 4100 J

User Littleguga
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1 Answer

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Final answer:

The change in heat associated with the change in water's temperature is 4100 J.

Step-by-step explanation:

The change in heat associated with the change in water's temperature can be calculated using the formula:

Change in heat = mass of water * specific heat capacity of water * change in temperature

In this case, the initial temperature of the water is 26.0°C and the final temperature is 39.0°C. The mass of the water is 75.0 g and the specific heat capacity of water is 4.19 J/gºC.

Using the formula, the change in heat is:

Change in heat = 75.0 g * 4.19 J/gºC * (39.0°C - 26.0°C)

Change in heat = 75.0 g * 4.19 J/gºC * 13.0°C

Change in heat = 4100 J

Therefore, the correct answer is 4100 J.

User Faslur Rajah
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8.5k points