Question

What is the speed of the car at time t = 3.0 s, given that it accelerates uniformly from rest at 2.2 m/s^2 for 3.0 s?

A) 6.6 m/s
B) 9.9 m/s
C) 13.2 m/s
D) 15.4 m/s

Answer 1

The speed of the car at time t = 3.0 s, given the uniform acceleration from rest at 2.2 m/s^2, is calculated using the equation v = v_0 + at. With v_0 being 0 m/s and a being 2.2 m/s^2, the final speed is 6.6 m/s.

Step-by-step explanation:

To find the speed of the car at time t = 3.0 s, we can use the equation of motion that relates initial velocity, acceleration, and time. Since the car starts from rest, its initial velocity (v0) is 0 m/s. The acceleration (a) is given as 2.2 m/s2. The equation we use is:

v = v0 + at

Substituting the given values:

v = 0 m/s + (2.2 m/s2)(3.0 s) = 6.6 m/s

Therefore, the speed of the car at t = 3.0 s is 6.6 m/s, which corresponds to option A.