Question

In parallelogram PQRS, where PQ is represented by part of the line y=3x+2 and QR is represented by part of the line y=(-2/5)x-9, what is the slope of RS and what was the slope of PS?

A. The slope of RS is 3.
B. The slope of RS is -2/5.
C. The slope of PS was 3.
D. The slope of PS was -2/5.
E. The slope of RS is 5/2.
F. The slope of RS is -3.

Answer 1

The slope of RS is 3 and the slope of PS was -2/5.

Step-by-step explanation:

The slope of a line can be found using the equation y = mx + b, where m represents the slope. In the given parallelogram PQRS, the slope of PQ, which is represented by the line y = 3x + 2, is 3. This means that for every 1 unit increase in x, y increases by 3 units.

Similarly, in the given parallelogram, the slope of QR, represented by the line y = (-2/5)x - 9, is -2/5. This means that for every 5 unit increase in x, y decreases by 2 units.

Since opposite sides of a parallelogram are parallel, the slope of RS is the same as the slope of PQ, which is 3. The slope of PS, on the other hand, would be the negative reciprocal of the slope of QR, which is -2/5. Therefore, the slope of PS was -2/5.