Final answer:
The charge on the aluminum ion in AlBr3 is +3, balancing the total -3 charge from three bromine ions with a charge of -1 each.
Step-by-step explanation:
If bromine forms ions with a charge of -1, the charge on the aluminum ion in AlBr3 must balance the total negative charge of the bromine ions. Since each bromine ion has a charge of -1 and there are three bromine ions in the compound, the total negative charge is -3. To balance this and make the compound neutral, the aluminum ion must have a +3 charge. Therefore, the correct answer is that the charge on the aluminum ion in AlBr3 is +3.