Question

There are 4 consecutive even integers that have a sum of - 12 . Which integers are they?

Answer 1

The four consecutive even integers that have a sum of -12 are -6, -4, -2, and 0.

Step-by-step explanation:

Let's represent the four consecutive even integers as x, x+2, x+4, and x+6. We can set up an equation to represent the sum of these integers:

x + (x+2) + (x+4) + (x+6) = -12

Combining like terms, we get 4x + 12 = -12

Subtracting 12 from both sides, we have 4x = -24

Dividing by 4, we find that x = -6

So the four consecutive even integers are -6, -4, -2, and 0.

Answer 2

To find the consecutive even integers that have a sum of -12, start by letting the first integer be x. The four consecutive even integers are -6, -4, -2, and 0.

Step-by-step explanation:

To find the consecutive even integers that have a sum of -12, we can start by letting the first integer be x. Since they are consecutive, the second integer will be x + 2, the third integer will be x + 4, and the fourth integer will be x + 6.

To find the sum of these integers, we can set up the equation: x + (x + 2) + (x + 4) + (x + 6) = -12.

Simplifying this equation, we get 4x + 12 = -12. Solving for x, we find that x = -6.

Therefore, the four consecutive even integers that have a sum of -12 are -6, -4, -2, and 0.