Question

Which of the following equations have infinitely many solutions?

Choose all answers that apply:
A .102 – 10 = -10x + 10
B .-10x – 10 = -102 - 10
C .-102 – 10 = -10 + 10
D .102 - 10 = -102 - 10

Answer 1

The equations A. 102 – 10 = -10x + 10 and C. -102 – 10 = -10 + 10 have infinitely many solutions.

Step-by-step explanation:

The equations that have infinitely many solutions are:

• A. 102 – 10 = -10x + 10
• B. -10x – 10 = -102 - 10
• C. -102 – 10 = -10 + 10

Let's analyze each equation:

A. 102 – 10 = -10x + 10: This equation can be simplified to 92 = -10x. By dividing both sides by -10, we get x = -9.2. So, there is only one solution.

B. -10x – 10 = -102 - 10: This equation can be simplified to -10x - 10 = -112. By adding 10 to both sides, we get -10x = -102. By dividing both sides by -10, we get x = 10.2. So, there is only one solution.

C. -102 – 10 = -10 + 10: This equation can be simplified to -112 = 0. This equation is always true for any value of x. Therefore, it has infinitely many solutions.

So, the correct answer is A and C.