Final answer:
Mr. Kamel's statement is incorrect. As the size of a cell increases, its surface area-to-volume ratio decreases, limiting its efficiency in exchanging nutrients and wastes. This is due to the fact that the volume of a cell increases more rapidly than its surface area.
Step-by-step explanation:
The statement made by Mr. Kamel is incorrect. As the size of a cell increases, its surface area-to-volume ratio decreases. The surface area of a cell is calculated using the formula 4πr², while the volume is calculated using the formula 4πr³/3. The ratio of surface area to volume is important because it determines the efficiency of a cell in exchanging nutrients and wastes with its environment.
For example, let's compare a spherical cell with a diameter of 5 µm and a cubed-shaped cell with a side length of 7 µm. The surface area-to-volume ratio of the spherical cell is 25.12 µm²/µm³, while the ratio of the cubed-shaped cell is 1.42 µm²/µm³. Since the surface area-to-volume ratio of the spherical cell is greater, it would exchange nutrients and wastes more efficiently with its environment.
Based on this information, we can conclude that as a cell increases in size, its surface area-to-volume ratio decreases, limiting the cell's ability to exchange nutrients and wastes efficiently.