Question

What mass of HBO2 is produced from the

combustion of 139.5 g of B2H6?
Answer in units of g.

Answer 1

`m_(HBO_2)=441.8gHBO_2`

Step-by-step explanation:

Hello there!

In this case, since the combustion of B2H6 is:

`B_2H_6+3O_2\rightarrow 2HBO_2+2H_2O`

Thus, since there is 1:2 mole ratio between the reactant and product, the produced grams of the latter is:

`m_(HBO_2)=139.5gB_2H_6*(1molB_2H_6)/(27.67gB_2H_6) *(2molHBO_2)/(1molB_2H_6) *(43.82gHBO_2)/(1molHBO_2)`

`m_(HBO_2)=441.8gHBO_2`

Best regards!