Question

The secondary coil consists of 20 loops and has an output voltage of 80 V. If the primary coil had 100 loops, what was the voltage across the primary coil?

A.80 V
B.25 V
C.400 V
D.20 V

Answer 1

To find the voltage across the primary coil, we can use the equation Vp / Vs = Np / Ns. Plugging in the values, we find that the voltage across the primary coil is 400 V.

Step-by-step explanation:

In a transformer, the ratio of the number of loops in the secondary coil to the number of loops in the primary coil is equal to the ratio of the output voltage across the secondary coil to the input voltage across the primary coil. Therefore, to find the voltage across the primary coil, we can use the equation:

Vp / Vs = Np / Ns

Where Vp is the voltage across the primary coil, Vs is the voltage across the secondary coil, Np is the number of loops in the primary coil, and Ns is the number of loops in the secondary coil.

In this case, the secondary coil has 20 loops and an output voltage of 80 V. The primary coil has 100 loops. Plugging these values into the equation, we get:

Vp / 80 = 100 / 20

Simplifying, we find that Vp = 400 V.