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The specific heat of liquid bromine is 0.226 J/g-K. How much heat (J) is required to raise the temperature of 10.0 Kg of bromine from 25.00 °C to 27.30 °C?

User JR White
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1 Answer

4 votes

Final answer:

To raise the temperature of 10.0 kg of bromine from 25.00 °C to 27.30 °C, it requires 4.52 kJ of heat.

Step-by-step explanation:

To calculate the amount of heat required, we can use the formula:

Q = mc∆T

Where:
Q is the heat transferred
m is the mass of the substance
c is the specific heat capacity of the substance
∆T is the change in temperature

Plugging in the values, we have:

Q = (10.0 kg)(0.226 J/g-K)(27.30 °C - 25.00 °C)

Q = 4.52 kJ

Therefore, it requires 4.52 kJ of heat to raise the temperature of 10.0 kg of bromine from 25.00 °C to 27.30 °C.

User Opher Lubzens
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