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ABC is an equilaterals of side a. Its area will be

(a) root 3^2/4a
(b) root 3/4a
(c) root 3/2a^2
(d) root 3/2a​

User Mcmwhfy
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1 Answer

4 votes

Final answer:

The area of an equilateral triangle with side length a is given by the formula (\(\sqrt{3}/4\)) \(a^2\), so the correct answer is (c) \(\sqrt{3}/4\) \(a^2\).

Step-by-step explanation:

The question is asking for the area of an equilateral triangle with side length a. The area of an equilateral triangle can be found using the formula:

Area = (\(\sqrt{3}/4\)) \(a^2\)

Therefore, the correct answer is (c) \(\sqrt{3}/4\) \(a^2\). To understand why this formula works, consider that equilateral triangles can be split into two 30-60-90 right triangles. Using the properties of these right triangles, given that each side of the equilateral triangle is a, the height (h) can be found using the formula:

h = a \(\sqrt{3}/2\)

Once we have the height, we can then apply the generic formula for the area of a triangle, which is:

Area = 1/2 \(\times\) base \(\times\) height

Substituting the expressions for base and height of the equilateral triangle:

Area = 1/2 \(\times\) a \(\times\) \(a \sqrt{3}/2\) = \(\sqrt{3}/4\) \(a^2\), which is the area of the equilateral triangle.

User Fxfuture
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