Question

Over a period of 20.0 seconds, a plane speeds up to its cruising speed. It accelerates at a rate of 3.0 m/s2. If it starts at a speed of 51.0, how far did it travel during the acceleration?​

Answer 1

The plane traveled 1620 meters while accelerating to its cruising speed with an initial speed of 51.0 m/s and an acceleration of 3.0 m/s² over 20 seconds.

Step-by-step explanation:

The question asks how far a plane travels while accelerating to its cruising speed from an initial speed of 51.0 m/s, with an acceleration of 3.0 m/s2 over a period of 20.0 seconds. To solve this, we can use the kinematic equation that relates distance (d), initial velocity (vi), acceleration (a), and time (t):

d = vi × t + ½ a × t2

Substituting the given values:

d = 51.0 m/s × 20.0 s + ½ × 3.0 m/s2 × (20.0 s)2

d = 1020 m + ½ × 3.0 m/s2 × 400 s2

d = 1020 m + 1.5 m/s2 × 400 s2

d = 1020 m + 600 m

Therefore, the total distance traveled during acceleration is 1620 meters.