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You collect 14.2 liters of CO gas from an experiment. How many molecules would be in the sample?

User Hitch
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2 Answers

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Final answer:

To find the number of CO gas molecules in a 14.2-liter sample, calculate the moles based on the volume and then use Avogadro's number to find that there are approximately 3.81 × 1023 molecules of CO.

Step-by-step explanation:

To determine how many molecules are in a 14.2-liter sample of CO gas at STP (Standard Temperature and Pressure), you first need to calculate the number of moles of CO gas.

By using the molar volume of a gas at STP, which is 22.414 liters per mole, you can find the number of moles and then use Avogadro's number to find the number of molecules.

  1. First, divide the volume of CO gas by the molar volume at STP to find the number of moles:
    14.2 L / 22.414 L/mol = 0.633 moles of CO.
  2. Then, use Avogadro's number (which is 6.022 × 1023 molecules/mol) to calculate the number of molecules in the sample:
    0.633 mol × 6.022 × 1023 molecules/mol = 3.81 × 1023 molecules of CO.

User Dthal
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1 vote

Final answer:

To calculate the number of CO molecules in a 14.2-liter sample at STP, divide the volume by 22.414 L/mol to get the number of moles and multiply by Avogadro's number, resulting in approximately 3.82 x 10^23 molecules.

Step-by-step explanation:

The student is asking how many molecules of carbon monoxide (CO) would be in a 14.2-liter sample of the gas. To find the number of molecules, we can use Avogadro's number and the ideal gas law. Under Standard Temperature and Pressure (STP), one mole of an ideal gas occupies 22.414 liters. Therefore, we can divide the volume of the gas by this molar volume to find the number of moles:

  1. Calculate the number of moles of CO by dividing the volume by the molar volume at STP: 14.2 L / 22.414 L/mol = 0.634 moles of CO.
  2. Multiply the number of moles by Avogadro's number (6.022 × 1023 molecules/mol) to find the number of molecules: 0.634 moles × 6.022 × 1023 molecules/mol = 3.82 × 1023 molecules of CO.

Therefore, 14.2 liters of CO gas at STP contains approximately 3.82 × 1023 molecules.

User Raviture
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