Final answer:
Given an effort of 300N applied 10cm from the fulcrum on a nut-cracker, and the nut placed 3cm from the fulcrum, by the principle of moments the force experienced by the nut is calculated to be 1000N.
Step-by-step explanation:
The question asks to calculate the force experienced by a nut in a nut-cracker, given that an effort of 300N is applied 10cm from the fulcrum, while the nut is placed 3cm from the fulcrum. In physics, particularly when dealing with simple machines like a lever, the principle of moments states that the torque (also called moment of force) on both sides of the fulcrum must be equal for the system to be in equilibrium. Torque is the product of the force applied and the distance from the fulcrum.
Using the formula effort × effort arm = load × load arm, we can calculate the force experienced by the nut (load) as follows:
Effort × Effort Arm = Load × Load Arm
300N × 10cm = Load × 3cm
Load = (300N × 10cm) / 3cm
Load = 3000N / 3cm
Load = 1000N
The nut experiences a force of 1000N due to the applied effort of 300N.