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What is the surface area of a cylindrical rod of height 17 cm and diameter 14 cm?(Take it = 22/7)

A. 788 cm
B. 902 cm
C. 1 056 cm
D. 2 728 cm​

User Nordin
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1 Answer

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Final answer:

The surface area of the cylindrical rod is approximately 1056 cm².

Step-by-step explanation:

The surface area of a cylindrical rod can be found by adding the areas of the two circular bases and the area of the curved surface (or lateral surface). The formula for the surface area of a cylinder is:

SA = 2πr² + 2πrh

Given that the height of the rod is 17 cm and the diameter is 14 cm, we can calculate the radius (r) by dividing the diameter by 2. So, r = 7 cm. Plugging in the values, we get:

SA = 2π(7)² + 2π(7)(17)

SA = 2π(49) + 2π(119)

SA = 98π + 238π

SA = 336π

To approximate the value of π, we can use 22/7 as given. So:

SA ≈ 336 × (22/7)

SA ≈ 336 × 3.14285714

SA ≈ 1056 cm²

Therefore, the surface area of the cylindrical rod is approximately 1056 cm².

User Paul Verschoor
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