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A gold rectangle bar has a mass of 697g and sides that measure 7.2cm, 3cm, and 2.6cm. what is the density (show all work and label)

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Final answer:

The density of the gold rectangle bar is calculated by dividing the mass (697 g) by the volume (56.16 cm³), resulting in a density of 12.41 g/cm³.

Step-by-step explanation:

To calculate the density of the gold rectangular bar, we need to find its volume and use the mass given. The volume of a rectangular object is the product of its length, width, and height. So, the volume of the gold bar is 7.2 cm × 3 cm × 2.6 cm which equals 56.16 cm³. Now, we take the mass of the gold bar, which is 697 g, and divide it by the volume to find the density.

Density = Mass / Volume
Density = 697 g / 56.16 cm³
Density = 12.41 g/cm³

The calculated density of the gold rectangle bar is therefore 12.41 g/cm³. This is less than the standard density of pure gold, which is 19.3 g/cm³, possibly suggesting impurities or a different material within the bar.

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