Question

A kid throws a skittle strait up in the air. It takes 4.2 seconds to reach its max height and fall back to the height it was thrown from. What was the initial velocity the skittle was thrown at?

Answer 1

The initial velocity of the skittle when thrown straight up is 41.16 m/s.

Step-by-step explanation:

To find the initial velocity of the skittle when thrown straight up, we can use the formula:

v = u + at

where v is the final velocity (0 m/s when it reaches max height), u is the initial velocity (what we are trying to find), a is the acceleration due to gravity (-9.8 m/s²), and t is the time taken to reach max height (4.2 seconds).

Plugging in these values, we can solve for u:

0 = u + (-9.8)(4.2)

u = 9.8(4.2)

u = 41.16 m/s

Therefore, the initial velocity of the skittle when thrown straight up is 41.16 m/s.