44.4k views
0 votes
Water has a specific heat of 4.186 j/g°c. How much heat is required to increase 10.0g of water from 25:0°c to 30.0°c?

User Debo
by
7.7k points

1 Answer

5 votes

Final answer:

To increase the temperature of 10.0g of water from 25.0°C to 30.0°C, 209.3 J of heat is required.

Step-by-step explanation:

To calculate the amount of heat required to increase the temperature of water, we can use the formula:

q = m × c × ΔT

where q is the heat, m is the mass of water, c is the specific heat of water, and ΔT is the change in temperature. Given that the mass of water is 10.0g, the specific heat of water is 4.186 J/g°C, and the change in temperature is 30.0°C - 25.0°C = 5.0°C, we can substitute these values into the formula:

q = (10.0g) × (4.186 J/g°C) × (5.0°C)

q = 209.3 J

Therefore, the amount of heat required to increase 10.0g of water from 25.0°C to 30.0°C is 209.3 J.

User Rosswil
by
7.9k points