Question

Based off the formula provided for you (a = 2d / t2) and the fact we know the acceleration due to gravity is 9.8 m/s2. How long should it have taken for the object to hit the ground? (Show your work).

**HINT: plug 9.8 in for a, the height you dropped it form for d and solve for t**
the height I dropped it from is 2 meters
Time = ___________________________
d = height object fell t = average time it took to hit ground

Answer 1

Using the formula a = 2d / t^2 where 'a' is gravity's acceleration (9.8 m/s^2) and 'd' is the height (2 meters), the time 't' for an object to hit the ground when dropped from 2 meters is approximately 0.639 seconds.

Step-by-step explanation:

To determine how long it should take for an object to hit the ground when dropped from a height of 2 meters, we can use the formula for uniformly accelerated motion, which in this case is the acceleration due to gravity. The formula is a = 2d / t^2, where 'a' is the acceleration (9.8 m/s2 for gravity), 'd' is the distance (2 meters, the height the object is dropped from), and 't' is the time in seconds. By substituting the values into the formula, we can solve for 't'.

Plugging in the known values gives us:

9.8 = 2(2) / t^2

After rearranging and solving for t, we get:

t^2 = 4 / 9.8

t = √(4 / 9.8)

= √(0.408163)

t = 0.639 seconds approximately.

Therefore, it should take approximately 0.639 seconds for the object to hit the ground when dropped from a height of 2 meters.