Question

A car had a velocity of 3 m/s, but over 10 seconds, it sped up to a velocity of 6 m/s.

How much acceleration did the car experience over the 10-second interval?

Options:
A) 0.3 m/s²
B) 0.6 m/s²
C) 0.9 m/s²
D) 1.2 m/s²

Answer 1

The car experienced an acceleration of 0.3 m/s² over the 10-second interval, calculated using the formula a = Δv / t, where Δv is the change in velocity, and t is time.

Step-by-step explanation:

To determine the acceleration the car experienced, we'll use the formula for acceleration (a), which is the change in velocity (Δv) divided by the time (t) it takes for that change to occur. The formula looks like this: a = Δv / t.

In this case, the initial velocity (vi) is 3 m/s, the final velocity (vf) is 6 m/s, and the time interval (t) is 10 seconds. The change in velocity (Δv) is the difference between the final and initial velocities: Δv = vf - vi = 6 m/s - 3 m/s = 3 m/s. Therefore, the acceleration can be calculated as follows:

a = Δv / t = 3 m/s / 10 s = 0.3 m/s².

So the car experienced an acceleration of 0.3 m/s² over the 10-second interval. The correct answer is option A) 0.3 m/s².