Final answer:
The two integers that satisfy the conditions given (sum of 40 and difference of 8) are 24 and 16.
Step-by-step explanation:
The sum of two integers is given as 40, and their difference is 8. To find these integers, we can set up two equations based on the given information. Let's call the integers x and y. From the problem, we know:
x + y = 40 (Equation 1)
x - y = 8 (Equation 2)
To solve for the integers, we can add Equation 1 and Equation 2 together:
x + y + x - y = 40 + 8
2x = 48
x = 24
Now, we substitute x back into Equation 1 to find y:
24 + y = 40
y = 40 - 24
y = 16
Therefore, the two integers are 24 and 16, which is choice (c).