Final answer:
The mass of Carbon Monoxide (CO) with the same number of oxygen atoms as in 88 grams of Carbon Dioxide (CO₂) is 112 grams. This is calculated based on the molar masses of CO₂ and CO and the stoichiometry of oxygen atoms in both molecules.
Step-by-step explanation:
To calculate the mass of Carbon Monoxide (CO) having the same number of oxygen atoms as present in 88 grams of Carbon Dioxide (CO₂), we need to consider the molar masses of both compounds. The molar mass of CO₂ is approximately 44 grams/mole (12 grams/mole for carbon and 16 grams/mole for each oxygen atom), and the molar mass of CO is approximately 28 grams/mole (12 grams/mole for carbon and 16 grams/mole for oxygen). Using this information, we can set up the following calculation:
Firstly, determine the moles of oxygen atoms in 88 grams of CO₂:
Number of moles of CO₂ = Mass / Molar mass = 88 g / 44 g/mole = 2 moles of CO₂
Since each mole of CO₂ contains 2 moles of oxygen atoms, we have:
Number of moles of O atoms in CO₂ = 2 moles of CO₂ x 2 = 4 moles of O
We need the same number of moles of oxygen atoms in CO. Since each mole of CO contains one mole of oxygen, the number of moles of CO needed is also 4.
Calculate the mass of CO having 4 moles of oxygen:
Mass of CO = Number of moles x Molar mass of CO = 4 moles x 28 g/mole = 112 g
Therefore, the mass of CO with the same number of oxygen atoms as in 88 grams of CO₂ is 112 grams.