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An object is shot upwards and then comes down with an initial velocity of 200 m/s. How high will it be after 4 seconds?

User Kupi
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1 Answer

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Final answer:

The object will be at a height of 878.4 meters after 4 seconds.

Step-by-step explanation:

To find the height of the object after 4 seconds, we can use the equation for vertical motion:

h = h0 + v0t - (1/2)gt^2

Where:

  • h is the final height
  • h0 is the initial height
  • v0 is the initial velocity
  • t is the time
  • g is the acceleration due to gravity

Given that the object comes down with an initial velocity of 200 m/s, we can assume the initial height is 0 and the acceleration due to gravity is -9.8 m/s^2 (negative because the object is coming down). Plugging these values into the equation gives:

h = 0 + 200(4) - (1/2)(-9.8)(4)^2

Simplifying:

h = 800 + 78.4 = 878.4 meters

Therefore, the object will be at a height of 878.4 meters after 4 seconds.

User Dude Bro
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