Question

A block with a mass of 150 kg is being pulled to the left by a string held at 30 degrees to the horizontal. A friction force of 32 N opposes the motion of the block. What is the tension in the string if the block goes from rest to 1.2 m/s in 5 s?

Answer 1

The tension in the string is 212 N.

Step-by-step explanation:

To find the tension in the string, we need to consider the forces acting on the block. The force of tension in the string is equal to the force required to accelerate the block, minus the force of friction opposing its motion.

Using Newton's second law, F_net = m * a, we can calculate the net force:

F_net = m * a = (150 kg) * (1.2 m/s^2) = 180 N

The force of friction opposing the motion is given as 32 N, so the tension in the string is:

Tension = F_net + force of friction = 180 N + 32 N = 212 N