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What is the gravitational potential energy of a 1 kg ball that is 2 meters

above the floor? (g=9.8 m/s)
30
9.8 J
19.6 J
29.8 J

User Tafaust
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7.4k points

1 Answer

5 votes

Final answer:

The gravitational potential energy of a 1 kg ball that is 2 meters above the floor, with an acceleration due to gravity of 9.8 m/s², is calculated using the formula GPE = mgh to be 19.6 J.

Step-by-step explanation:

The question pertains to calculating the gravitational potential energy of a 1 kg ball that is 2 meters above the floor. The formula for the gravitational potential energy (GPE) is given by GPE = mgh, where m stands for mass, g is the acceleration due to gravity, and h is the height above the reference point.

In this case, the mass (m) is 1 kg, gravity (g) is 9.8 m/s² (as given in the question), and the height (h) is 2 meters. Plugging these values into the formula yields:

GPE = 1kg * 9.8 m/s² * 2m = 19.6 J

Therefore, the gravitational potential energy of the ball is 19.6 Joules (J).

User Freek Wiekmeijer
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