The equation of the line perpendicular to y=2x that passes through (-1, -3) is y = -1/2x - 5/2, found by using the negative reciprocal of the given line's slope.
The equation of the line perpendicular to the line y=2x that passes through the point (-1, -3) is y = -1/2x - 5/2.
To find the perpendicular line we need the negative reciprocal of the original slope (which is 2). This gives us a slope of -1/2 for the perpendicular line. Using the point-slope form and the coordinates of the given point, we can find the y-intercept, which leads to the equation of the line.
the process of finding the equation of a line perpendicular to a given line involves identifying the negative reciprocal of the given line's slope and using the point-slope form to include the point through which the perpendicular line passes.