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A block weighing (mg) 35 N is resting on a steel table ( us= 0.40). The minimum force to start this block moving is _ N.

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Final answer:

The minimum force required to start the block moving is 14 N.

Step-by-step explanation:

To determine the minimum force required to start the block moving, we need to consider the frictional force acting on the block. The frictional force can be calculated using the equation F_friction = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force.

In this case, the normal force N is equal to the weight of the block, which is mg. Therefore, N = 35 N.

Given that the coefficient of static friction μ_s is 0.40, the frictional force F_friction = 0.40 * 35 N = 14 N.

So, the minimum force required to start the block moving is equal to the frictional force, which is 14 N.

User Egor Wexler
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