Final answer:
To heat from 25°C to 45°C, 20 kg of aluminum would require the most energy compared to 20 kg of water or steel.
Step-by-step explanation:
To calculate the amount of energy required to heat a substance, we need to use the equation Q = mcΔT, where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
Water has a specific heat capacity of 4186 J/(kg-°C), aluminum has a specific heat capacity of 900 J/(kg-°C), and steel has a specific heat capacity of 450 J/(kg-°C). To determine which substance would require the most energy to heat from 25°C to 45°C, we calculate the value of Q for each substance.
- Water: Q = (20 kg) × (4186 J/(kg-°C)) × (45°C - 25°C) = 167,440 J
- Aluminum: Q = (20 kg) × (900 J/(kg-°C)) × (45°C - 25°C) = 360,000 J
- Steel: Q = (20 kg) × (450 J/(kg-°C)) × (45°C - 25°C) = 180,000 J
Based on these calculations, it can be determined that heating 20 kg of aluminum from 25°C to 45°C would require the most energy.