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Let n be equal to 182% of 60. Which of the following proportions is true?

A. 182/60=n/100.
B. 182/100=n/60.
C. 60/100=182/n.
D. 60/128=n/100

User Miji
by
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1 Answer

1 vote

Final answer:

The correct proportion is option B: 182/100 = n/60.

Step-by-step explanation:

To solve this problem, we can set up a proportion using the given information. Let n be equal to 182% of 60:

  1. Option A: 182/60 = n/100. This proportion is not true because it does not match the given information.
  2. Option B: 182/100 = n/60. This proportion is true because it correctly shows that 182% of 60 is equal to n.
  3. Option C: 60/100 = 182/n. This proportion is not true because it does not match the given information.
  4. Option D: 60/128 = n/100. This proportion is not true because it does not match the given information.

Therefore, the correct proportion is option B: 182/100 = n/60.

User Roman Pominov
by
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