Question

Calcium metal will react with iodine to produce solid aluminum iodide according to the unbalanced equation: Caco + Cal2(s). If three moles of Calcium metal and four moles of iodine, how many moles of Calcium iodide could be produced in this reaction.

Answer 1

In the given chemical reaction between calcium and iodine, when 3 moles of calcium and 4 moles of iodine are used, 4 moles of calcium iodide can be produced.

Step-by-step explanation:

The balanced equation for the reaction between calcium and iodine is:

Ca + I2 -> CaI2

From the equation, we can see that 1 mole of calcium reacts with 1 mole of iodine to produce 1 mole of calcium iodide.

Given that we have 3 moles of calcium and 4 moles of iodine, we can use the stoichiometry of the reaction to determine the number of moles of calcium iodide that can be produced.

1. First, we determine the limiting reactant by comparing the moles of calcium and iodine. Since we have more iodine than calcium, calcium is the limiting reactant.
   
2. Next, we use the stoichiometry of the reaction to calculate the moles of calcium iodide. Since 1 mole of calcium reacts with 1 mole of iodine to produce 1 mole of calcium iodide, we can generate a ratio:

1 mole calcium iodide / 1 mole iodine

Finally, we multiply the ratio by the number of moles of iodine:

1 mole calcium iodide / 1 mole iodine * 4 moles iodine = 4 moles calcium iodide

Therefore, with 3 moles of calcium and 4 moles of iodine, you can produce 4 moles of calcium iodide.