90.7k views
1 vote
On the interval 0 < x < 2n, what are the x-intercepts of y = sinx?

1. 0, 3.14/2, and 3 3.14/2
2. 0, 3.14, and 2 3.14
3. 3.14/2 and 3 3.14/2 only
4. 3.14 and 2 3.14 only

User EddyR
by
7.3k points

1 Answer

0 votes

Final answer:

The x-intercepts of y = sin(x) on the interval 0 < x < 2π are at π and 2π only.

Step-by-step explanation:

You're asking about the x-intercepts of the function y = sin(x) on the interval 0 < x < 2π. An x-intercept is a point where the graph of a function crosses the x-axis, which means y=0. For the sine function, this occurs at every integer multiple of π within the given interval. So on the interval 0 < x < 2π, the x-intercepts occur at x = π and x = 2π. Since 0 and 2π are at the endpoints of the interval and not included within it, the only x-intercept within the interval is at x = π. Hence, the correct answer is π and 2π only.

User Javy
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories