Question

How many liters of O2 are present in 175 grams O2? (32.00 grams O2 per 1 mole Oz, also 22.4 L 02 per 1 mole Oz)

Answer 1

To find out how many liters of O₂ are present in 175 grams of O₂, convert the mass to moles using the molar mass and then convert moles to liters using the molar volume at STP, to get 122.5 liters of O₂.

Step-by-step explanation:

To determine how many liters of O₂ are in 175 grams of O₂, you need to follow these steps:

1. First, establish the mass of O₂, which is given as 175 grams.

2. Next, use the molar mass of O₂, which is 32.00 grams per mole, to convert grams to moles:

3. 175 g O₂ × (1 mol O₂ / 32.00 g O₂) = 5.46875 mol O₂

4. Lastly, convert moles of O₂ to volume using the molar volume of a gas at STP (Standard Temperature and Pressure), which is 22.4 liters per mole:

5. 5.46875 mol O₂ × (22.4 L O₂ / 1 mol O₂) = 122.5 liters of O₂