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How many electrons are passing through a point in a copper wire in 2 seconds when the wire carries a current of 1 ampere? Given that the charge on each electron, e =1.6x10⁻¹⁹ C​

User BrunoRB
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Final answer:

The number of electrons passing through a point in a copper wire carrying a current of 1 ampere in 2 seconds can be calculated using the equation: Number of electrons passing through = (Current) x (Time) x (6.25 × 10^18 electrons/ampere-second). Therefore, the total number of electrons passing through the point would be 1.25 × 10^19 electrons.

Step-by-step explanation:

The electric current moving through a wire is the flow of electric charge. In this case, the wire is carrying a current of 1 ampere. By definition, 1 ampere is the flow of one coulomb of charge through an area in one second. We can determine the number of electrons passing through a point in the copper wire in 2 seconds by considering that 1 ampere is equivalent to 6.25 × 10^18 electrons flowing through the area each second.



So, in 2 seconds, the total number of electrons passing through the point in the copper wire can be calculated as follows:

Number of electrons passing through = (1 ampere) x (2 seconds) x (6.25 × 10^18 electrons/ampere-second) = 1.25 × 10^19 electrons

User ChrisFreeman
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