Question

An object with an initial velocity of 10 m/s accelerates at a rate of 3.5m/s squared for 8 seconds. How far will it have traveled during that time?

Answer 1

Using the kinematic equation s = ut + ½ at², the object with an initial velocity of 10 m/s and accelerating at 3.5 m/s² for 8 seconds will have traveled 192 meters.

Step-by-step explanation:

To determine how far an object has traveled during acceleration, we can use the kinematic equation for uniformly accelerated motion:

s = ut + ½ at²

Where:

• s is the displacement
• u is the initial velocity
• t is the time
• a is the acceleration

Given an initial velocity of 10 m/s, acceleration of 3.5 m/s², and time of 8 seconds, the equation becomes:

s = (10 m/s)(8 s) + ½ (3.5 m/s²)(8 s)²

s = 80 m + ½ (3.5 m/s²)(64 s²)

s = 80 m + (2 m/s)(64 s²)

s = 80 m + 112 m

s = 192 m

Thus, the object will have traveled 192 meters during that time.