Final answer:
To solve this problem, we can use algebra to set up a system of equations. By solving the system, we find that 10 tickets were sold for $3. Therefore, the correct answer is D) 20 tickets.
Step-by-step explanation:
To solve this problem, let's use algebra. Let's say the number of tickets sold for $3 is x, and the number of tickets sold for $5 is y.
According to the problem, we know that x + y = 50 (since a total of 50 tickets were sold) and 3x + 5y = 230 (since the total cost of the tickets sold is $230).
Now, we can solve this system of equations to find the values of x and y. Solving the first equation for x, we get x = 50 - y. Substituting this value into the second equation, we get 3(50 - y) + 5y = 230. Simplifying this equation, we get 150 - 3y + 5y = 230. Combining like terms, we have 2y = 80. Dividing both sides by 2, we find y = 40.
Substituting this value back into the first equation, we find x = 50 - 40 = 10. Therefore, 10 tickets were sold for $3. So, the correct answer is option D) 20 tickets.