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Write the expression using the fewest numbers of bases possible . Let a and b the positive intergers 24^a * 23 b

A) (24 * 23)^(a + b)
B) 24^(a + b) * 23^(a + b)
C) (24 * 23)^(a * b)
D) 24^(a * b) * 23^(a * b)

User Vijju
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1 Answer

5 votes

Final answer:

The expression that uses the fewest number of bases is option B) 24^(a + b) * 23^(a + b).

Step-by-step explanation:

The expression that uses the fewest number of bases is option B) 24(a + b) * 23(a + b).

To understand why, let's break down each option:

  • Option A) (24 * 23)(a + b): This uses 2 bases, 24 and 23.
  • Option B) 24(a + b) * 23(a + b): This uses 2 bases, 24 and 23, just like option A.
  • Option C) (24 * 23)(a * b): This uses 2 bases, 24 and 23, just like option A and B.
  • Option D) 24(a * b) * 23(a * b): This uses 2 bases, 24 and 23, just like option A, B, and C.

Therefore, option B) uses the fewest number of bases with a total of 2 bases.

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User Adam Young
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