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A 5.50 mole sample of gas has a volume of 2.50 L. What would be the volume if the amount increased to 11.0 moles?

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Final answer:

Using Avogadro's law, the volume of the gas would double to 5.00 L if the amount of gas is doubled from 5.50 moles to 11.0 moles, assuming constant temperature and pressure.

Step-by-step explanation:

The question posed by the student involves a gas law principle known as Avogadro's law, which states that the volume of a gas, at constant temperature and pressure, is directly proportional to the number of moles of the gas. In this case, if we keep temperature and pressure constant and the amount of gas initially is 5.50 moles with a volume of 2.50 L, doubling the number of moles to 11.0 should also double the volume.

We can write this as a direct proportion: V1/n1 = V2/n2, where V1 and n1 are the initial volume and amount, and V2 and n2 are the final volume and amount. Plugging in the values, we get: (2.50 L / 5.50 moles) = (V2 / 11.0 moles). Solving for V2 gives us a volume of 5.00 L.

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