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A jury consists of 5 men and 7 women. 3 jury members are selected at random for an interview. Find the probability that at least one is male.

A) 92%
B) 88%
C) 84%
D) 80%

1 Answer

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Final answer:

To find the probability that at least one member selected for an interview is male from a jury consisting of 5 men and 7 women, calculate the probability that all 3 selected members are women and subtract it from 1. The probability of at least one male being selected for an interview is 97/132 or approximately 73.48%.

Step-by-step explanation:

To find the probability that at least one member selected for an interview is male from a jury consisting of 5 men and 7 women, we will calculate the probability that all 3 selected members are women and subtract it from 1. The probability of selecting a woman for the first interview is 7/12, since there are 7 women out of 12 jury members. The probability of selecting a woman for the second interview, given that the first interviewee is a woman, is 6/11, and the probability of selecting a woman for the third interview, given that the first two interviewees are women, is 5/10. So the probability of selecting 3 women for the interview is (7/12) * (6/11) * (5/10) = 35/132. Therefore, the probability of at least one male being selected for an interview is 1 - 35/132 = 97/132, which is approximately 0.7348 or 73.48%.

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