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water flows with a velocity of 3 m/s in an 80-cm-diameter sewer pipe at a depth of 30 cm. the flow rate is nearest:

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Final answer:

The flow rate of water through the pipe is 1.5072 m^3/s.

Step-by-step explanation:

The flow rate of water through a pipe is given by the equation:

Q = A * v

where Q is the flow rate, A is the cross-sectional area of the pipe, and v is the velocity of the water.

In this question, the pipe has a diameter of 80 cm, which means the radius is 40 cm or 0.4 m. The cross-sectional area of the pipe is given by:

A = π * r2

Plugging in the values, we get:

A = 3.14 * (0.4)^2

A = 0.5024 m2

The velocity of the water is given as 3 m/s.

Using the formula for flow rate, we can calculate it:

Q = A * v

Q = 0.5024 * 3

Q = 1.5072 m3/s

So, the flow rate of water in the pipe is approximately 1.5072 m3/s.

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