Final answer:
To find the horizontal velocity with which Jack launched himself, we first determine the time taken to fall from 50 meters using kinematic equations, and then use this time to calculate the horizontal velocity given the 100 meters horizontal distance landed.
Step-by-step explanation:
The student is asking about finding the initial horizontal velocity of a stuntman, Jack, who projects himself from a height of 50 meters and lands a horizontal distance of 100 meters away. To solve this, we will use the kinematic equations for projectile motion, given that the motion is horizontally launched from an elevated position.
We'll need to find the time it takes for Jack to fall 50 meters vertically to the ground, ignoring air resistance and using the acceleration due to gravity. This time 't' is found using the equation t = √(2h/g), where 'h' is the height and 'g' is the acceleration due to gravity (9.81 m/s2). Then we use the equation for horizontal motion x = Uxt, where 'x' is the horizontal distance, 'Ux' is the horizontal velocity, and 't' is time. Solving for 'Ux' gives us the horizontal velocity with which Jack projected himself.