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Calculate the percent ionization of a 0.10M solution of acetic acid with a ph of 2.89

User Yvet
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Final answer:

The percent ionization of a 0.10M solution of acetic acid with a pH of 2.89 is 1.29%.

Step-by-step explanation:

To calculate the percent ionization of a 0.10M solution of acetic acid with a pH of 2.89, you must first determine the concentration of hydronium ions ([H3O+]) in the solution.

The pH is the negative logarithm of the hydronium ion concentration, so [H3O+] can be calculated using the equation:

[H3O+] = 10-pH

For a pH of 2.89:

[H3O+] = 10-2.89

= 1.29 x 10-3 M

This concentration [H3O+] is also the concentration of the acetic acid that ionized since they are in a 1:1 ratio. To find the percent ionization, divide the concentration of ionized acetic acid by the initial concentration and multiply by 100:

Percent ionization = ยก([H3O+] / Initial Concentration of Acetic Acid) x 100

Percent ionization = (1.29 x 10-3 M / 0.10 M) x 100

Percent ionization = 1.29%

User RWGodfrey
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